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A Charged Capacitor Has an Initial Electric Field E0 and Potential

Question 125

Multiple Choice

  A charged capacitor has an initial electric field E<sub>0</sub> and potential difference V<sub>0</sub> across its plates. Without connecting any source of emf, you insert a dielectric κ > 1)  slab between the plates to produce an electric field E<sub>d</sub> and a potential difference V<sub>d</sub> across the capacitor. The pair of statements that best represents the relationships between the electric fields and potential differences is A)  E<sub>d</sub> > E<sub>0;</sub> V<sub>d</sub> > V<sub>0</sub>. B)  E<sub>d</sub> = E<sub>0;</sub> V<sub>d</sub> > V<sub>0</sub>. C)  E<sub>d </sub>> E<sub>0;</sub> V<sub>d</sub> = V<sub>0</sub>. D)  E<sub>d</sub> < E<sub>0;</sub> V<sub>d</sub> > V<sub>0</sub>.<sub> </sub> E)  E<sub>d</sub> < E<sub>0;</sub> V<sub>d</sub> < V<sub>0</sub>.<sub> </sub> A charged capacitor has an initial electric field E0 and potential difference V0 across its plates. Without connecting any source of emf, you insert a dielectric κ > 1) slab between the plates to produce an electric field Ed and a potential difference Vd across the capacitor. The pair of statements that best represents the relationships between the electric fields and potential differences is


A) Ed > E0; Vd > V0.
B) Ed = E0; Vd > V0.
C) Ed > E0; Vd = V0.
D) Ed < E0; Vd > V0.
E) Ed < E0; Vd < V0.

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