0 kg · m², the constant force F is 39.2 N, and the radius r is 0.800 m. The wheel starts from rest. When the force has acted through 2.00 m, the rotational velocity acquired by the wheel due to this force will be A) 1.26 rad/s. B) 3.33 rad/s. C) 3.61 rad/s. D) 6.24 rad/s. E) 10.3 rad/s.

Question

Quizplus · Accepted Answer

We can use the equation for rotational motion: 
ω^2 = ω0^2 + 2αθ 
where ω0 = 0 (initial angular velocity), α = F/(mr) (angular acceleration), and θ = 2.00 m/r (angular displacement). 
Solving for ω, we get: 
ω = sqrt(2αθ) = sqrt(2(F/(mr))(2.00 m/r)) = sqrt(4F/m) 
Plugging in the values given, we get: 
ω = sqrt(4(39.2 N)/0.500 kg) = 3.61 rad/s 
Therefore, the answer is C.

0 Kg · M2, the Constant Force F Is 39

0 Kg · M², the Constant Force F Is 39