A mass m = 0.5 kg is hung from a pulley with moment of inertia I = 0.20 kg  m² and radius R = 10 cm. There is friction in the pulley. The mass is dropped from rest, and after 2 s it traveled 4 m. What is the angular acceleration of the pulley? A) 2 rad/s² B) 5 rad/s² C) 10 rad/s² D) 20 rad/s² E) 40 rad/s²

Question

Quizplus · Accepted Answer

We can use the equations of motion to solve for the angular acceleration of the pulley.

First, we can find the acceleration of the mass using the equation:

d = vit + 0.5at^2

where d = 4m, vi = 0, t = 2s

Solving for a, we get:

a = 4m / (2s)^2 = 1m/s^2

Next, we can use the equation:

a = alpha * R

where alpha is the angular acceleration of the pulley. Solving for alpha, we get:

alpha = a / R = 1m/s^2 / 0.1m = 10 rad/s^2

Therefore, the answer is D) 20 rad/s^2.

A Mass M = 0