Given that Z is a standard normal random variable, P(-1.23 $\le$ Z $\le$1.89) is: $\begin{array}{|l|l|}
\hline\text { A. } & 0.1903 . \
\hline \text { B. } & 0.9706 . \
\hline \text { C. } & 0.8907 . \
\hline \text { D. } & 0.7803 . \
\hline
\end{array}$

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The Answer of Given that Z is a standard normal random variable, P(-1.23 $\le$ Z $\le$1.89) is: $\begin{array}{|l|l|}
\hline\text { A. } & 0.1903 . \
\hline \text { B. } & 0.9706 . \
\hline \text { C. } & 0.8907 . \
\hline \text { D. } & 0.7803 . \
\hline
\end{array}$

Given That Z Is a Standard Normal Random Variable, P(-1 ≤\le≤

Given That Z Is a Standard Normal Random Variable, P(-1 $\le$