Given that the random variable X is normally distributed with a mean of 20 and a standard deviation of 7, P(28 $\le$ X $\le$30) is: $\begin{array}{|l|l|}
\hline \text { A. } & 2 \
\hline \text { B. } & 0.0507 . \
\hline \text { C. } & 0.8729 \
\hline \text { D. } & 0.9236 \
\hline
\end{array}$

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The Answer of Given that the random variable X is normally distributed with a mean of 20 and a standard deviation of 7, P(28 $\le$ X $\le$30) is: $\begin{array}{|l|l|}
\hline \text { A. } & 2 \
\hline \text { B. } & 0.0507 . \
\hline \text { C. } & 0.8729 \
\hline \text { D. } & 0.9236 \
\hline
\end{array}$

Given That the Random Variable X Is Normally Distributed with a Mean