If P(A) = 0.65, P(B) =0.76 and P(A$\cap$ B) =0.80, then P(A $\cup$ B) is: $\begin{array}{|l|l|}
\hline\text { A. } & 0.65 \
\hline \text { B. } & 0.61 . \
\hline \text { C. } & 0.80 \
\hline \text { D. } & 0.02 \
\hline
\end{array}$

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The Answer of If P(A) = 0.65, P(B) =0.76 and P(A$\cap$ B) =0.80, then P(A $\cup$ B) is: $\begin{array}{|l|l|}
\hline\text { A. } & 0.65 \
\hline \text { B. } & 0.61 . \
\hline \text { C. } & 0.80 \
\hline \text { D. } & 0.02 \
\hline
\end{array}$

If P(A) = 0 ∩\cap∩ B) =080, Then P(A ∪\cup∪ B) Is

If P(A) = 0 $\cap$ B) =080, Then P(A $\cup$ B) Is