If P(A) = 0.35, P(B) = 0.45 and P(A $\cap$ B) =0.20, then P(A | B) is: $\begin{array}{|l|l|}
\hline\text { A. } & 0.80 \
\hline \text { B. } & 0.60 \
\hline \text { C. } & 0.44 \
\hline \text { D. } & 0.57 \
\hline
\end{array}$

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The Answer of If P(A) = 0.35, P(B) = 0.45 and P(A $\cap$ B) =0.20, then P(A | B) is: $\begin{array}{|l|l|}
\hline\text { A. } & 0.80 \
\hline \text { B. } & 0.60 \
\hline \text { C. } & 0.44 \
\hline \text { D. } & 0.57 \
\hline
\end{array}$

If P(A) = 0 ∩\cap∩ B) =020, Then P(A | B) Is

If P(A) = 0 $\cap$ B) =020, Then P(A | B) Is