When Karl Kaveman adds chilled grog to his new granite mug, he removes 10.9 kJ of energy from the mug. If it has a mass of 625 g and was at 25$\degree$C, what is its new temperature? Specific heat capacity of granite = 0.79 J/(g ? K)

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The correct answer is A.The change in temperature is given by:$$\Delta T = \frac{Q}{mc_p}$$where:* Q is the energy removed from the mug* m is the mass of the mug* c_p is the specific heat capacity of graniteSubstituting the given values into the equation, we get:$$\Delta T = \frac{-10.9 kJ}{(625 g)(0.79 J/(g ? K))}$$$$\Delta T = -22.3\degree C$$The new temperature of the mug is therefore:$$25\degree C + (-22.3\degree C) = 3\degree C$$

When Karl Kaveman Adds Chilled Grog to His New Granite °\degree°

When Karl Kaveman Adds Chilled Grog to His New Granite $\degree$