Calculate$\Delta$S $\degree$for the reaction

Question

Quizplus · Accepted Answer

Using the formula for Gibbs free energy change:
ΔG = ΔH - TΔS

We have:
ΔG = 0 (because reaction is at equilibrium)
ΔH = F1F1F1S1 - F1F1F1S1F1F1F10
ΔS = F1F1F10S1 - F1F1F1S1

Rearranging the equation, we get:
ΔS = (F1F1F1S1 - F1F1F1S1F1F1F10)/T

Substituting the given values,
0 = F1F1F1S1 - F1F1F1S1F1F1F10 - T (F1F1F10S1 - F1F1F1S1)

Simplifying the equation, we get:
TΔS = F1F1F1S1 - F1F1F1S1F1F1F10 - F1F1F1S1 + F1F1F10S1
TΔS = F1F1F10S1 - F1F1F1S1F1F1F10

Substituting the given values in the above equation, we get:
TΔS = 198.02 J/K

Therefore, the answer is B.

Calculate Δ\DeltaΔ S °\degree° For the Reaction A) -254