What is the minimum frequency of a photon that can eject a photoelectron from Ba metal? (The work function of barium is $\varPhi$ = 4.3 *10^-19 J.)

Question

Quizplus · Accepted Answer

The minimum frequency of a photon required to eject a photoelectron is given by the equation $ f = \frac{\Phi}{h} $, where $\Phi$ is the work function and $h$ is Planck's constant ($6.626 \times 10^{-34} \, \text{J s}$). Substituting the given work function $\Phi = 4.3 \times 10^{-19} \, \text{J}$, we find $ f \approx 6.5 \times 10^{14} \, \text{Hz}$.

What Is the Minimum Frequency of a Photon That Can Φ\varPhiΦ

What Is the Minimum Frequency of a Photon That Can $\varPhi$