What is the energy (E, in joules) of the 514.5 nm photons emitted by an argon-ion laser?

Question

Quizplus · Accepted Answer

The energy of a photon can be calculated using the formula $E = \frac{hc}{\lambda}$, where $h$ is Planck's constant ($6.626 \times 10^{-34} \, \text{Js}$), $c$ is the speed of light ($3.00 \times 10^8 \, \text{m/s}$), and $\lambda$ is the wavelength of the light (in meters). Converting 514.5 nm to meters (514.5 nm = $514.5 \times 10^{-9}$ m) and substituting the values into the formula gives an energy value close to the one in option D.

What Is the Energy (E, in Joules) of the 514