How many liters of 0.200 M NaOH are required to completely neutralize 1.00 L of 0.100 M HCN?

Question

Quizplus · Accepted Answer

The neutralization reaction between NaOH and HCN is a 1:1 molar ratio. Therefore, the moles of NaOH needed are equal to the moles of HCN present. Since there are 0.100 moles of HCN in 1.00 L of 0.100 M solution, you need 0.100 moles of NaOH. Using the concentration of NaOH (0.200 M), the volume required is 0.100 moles / 0.200 M = 0.500 L.

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