Vinegar contains acetic acid (CH₃COOH, 60.06 g/mol).The acetic acid in a 12.0 g sample of vinegar was neutralized by 48.0 mL of 0.250 M NaOH.What is the mass percent CH₃COOH in this type of vinegar?

Question

Quizplus · Accepted Answer

The moles of NaOH used are 0.012 mol (48.0 mL * 0.250 M). Since the reaction is 1:1, moles of CH3COOH are also 0.012 mol. The mass of CH3COOH is 0.012 mol * 60.06 g/mol = 0.72072 g. The mass percent is (0.72072 g / 12.0 g) * 100% = 6.01%.

Vinegar Contains Acetic Acid (CH3COOH, 60

Vinegar Contains Acetic Acid (CH₃COOH, 60