A food sample was burned in a bomb calorimeter containing 786 mL water.How much thermal energy was produced when the temperature of the water [c_v = 4.148 J/g .$\degree$C)] and the calorimeter rose from 20.00$\degree$C to 23.91$\degree$C? The metal calorimeter had a heat capacity of 1053 J/$\degree$C without the water.

Question

Quizplus · Accepted Answer

The thermal energy produced can be calculated using the formula: q = (mass of water * specific heat of water * temperature change) + (heat capacity of calorimeter * temperature change). The mass of water is 786 g (since 1 mL of water is approximately 1 g), the specific heat of water is 4.148 J/g°C, and the temperature change is 3.91°C. Calculating gives: q = (786 g * 4.148 J/g°C * 3.91°C) + (1053 J/°C * 3.91°C) = 12700 J + 4113 J = 16813 J = 16.8 kJ.

A Food Sample Was Burned in a Bomb Calorimeter Containing °\degree°

A Food Sample Was Burned in a Bomb Calorimeter Containing $\degree$