The Equilibrium Constant for the Formation of Calcium Carbonate from the Ions

The equilibrium constant for the formation of calcium carbonate from the ions in solution is 2.2 *10⁸ according to the reaction Ca²⁺(aq) + CO₃^{2 -} (aq) ⇄ CaCO₃ (s) .What is the value of the equilibrium
Constant for the reverse of this reaction?

A) the same, 2.2 *10⁸
B) (-2.2 *10⁸)
C) 2.2 *10^-8
D) 4.5 * 10^-9
E) 4.5 *10⁹