For the chemical equilibrium aA + bB ⇄ cC, the value of the equilibrium constant K is 10.What is the value of the equilibrium constant for the reaction 2aA+2bB ⇄ 2cC?

Question

Quizplus · Accepted Answer

When the coefficients in a balanced chemical equation are multiplied by a factor (in this case, 2), the equilibrium constant for the new equation is the original equilibrium constant raised to the power of that factor. Therefore, $K_{new} = K_{original}^{factor}$, which in this case is $10^2 = 100$.

For the Chemical Equilibrium AA + BB ⇄ CC, the Value