The values of H rxn and S rxn are shown for the following equilibrium reaction.What makes the equilibrium constant larger at lower temperatures? 2 NO2 (g) ⇄ N2 O4 (g) H = -58.02 kJ/mol, S = -176.5 J/mol · K
A) The negative value of H is dominant at all temperatures.
B) The negative value of S is dominant at all temperatures.
C) The negative value of S is combined with the small value of T.
D) The negative value of H is combined with the small value of T.
Correct Answer:
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