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Question 131
∫((lnz)2+2lnz)dz=z(lnz)2+2zlnz−z+C\int\left((\ln z)^{2}+2 \ln z\right) d z=z(\ln z)^{2}+2 z \ln z-z+C∫((lnz)2+2lnz)dz=z(lnz)2+2zlnz−z+C .
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