SCENARIO 9-6
The quality control engineer for a furniture manufacturer is interested in the mean amount of force necessary to produce cracks in stressed oak furniture.She performs a two-tail test of the null hypothesis that the mean for the stressed oak furniture is 650 pounds.The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-Referring to Scenario 9-6, if the test is performed with a level of significance of 0.10, the engineer can conclude that the mean amount of force necessary to produce cracks in stressed oak furniture is 650 pounds.

Question

Quizplus · Accepted Answer

The engineer cannot conclude that the mean amount of force necessary to produce cracks is exactly 650 pounds based on the p-value and significance level. The p-value of 0.080 being less than the significance level of 0.10 means that there is enough evidence to reject the null hypothesis, suggesting that the mean might not be 650 pounds.

SCENARIO 9-6 The Quality Control Engineer for a Furniture Manufacturer Is Interested