SCENARIO 9-6 The quality control engineer for a furniture manufacturer is interested in the mean amount of force in pounds necessary to produce cracks in stressed oak furniture.She performs a two-tail test of the null hypothesis that the mean for the stressed oak furniture is 650 pounds.The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-Referring to Scenario 9-6, suppose the engineer had decided that the alternative hypothesis to test was that the mean was greater than 650 pounds.What would be the p-value of this one-tail test?
A)0.040
B)0.160
C)0.840
D)0.960

Question

Quizplus · Accepted Answer

Since the two-tail test resulted in a p-value of 0.080, for a one-tail test, we divide this value by 2, resulting in a p-value of 0.040. This is because the one-tail test only considers one direction of deviation from the null hypothesis, effectively halving the p-value of the two-tail test.

SCENARIO 9-6 the Quality Control Engineer for a Furniture Manufacturer