SCENARIO 9-6 The quality control engineer for a furniture manufacturer is interested in the mean amount of force in pounds necessary to produce cracks in stressed oak furniture.She performs a two-tail test of the null hypothesis that the mean for the stressed oak furniture is 650 pounds.The calculated value of the Z test statistic is a positive number that leads to a p-value of 0.080 for the test.
-Referring to Scenario 9-6, if the test is performed with a level of significance of 0.10, the engineer can conclude that the mean amount of force necessary to produce cracks in stressed oak furniture is 650 pounds.

Question

Quizplus · Accepted Answer

Since the p-value (0.080) is greater than the level of significance (0.10), the null hypothesis cannot be rejected. Therefore, the engineer cannot conclude that the mean amount of force necessary to produce cracks in stressed oak furniture is 650 pounds at a level of significance of 0.10.

SCENARIO 9-6 the Quality Control Engineer for a Furniture Manufacturer