Question 1

Figure 6-4
-Given the circuit in Figure 6-4, find the total current It).
A) 0.187 A
B) 24.8 mA
C) 0.024 A
D) 375 mA

Accepted Answer

D

Question 2

-Given the circuit in Figure , what is the total equivalent) resistance of the circuit? 
A) 100 Ω
B) 600 Ω
C) 300 Ω/3
D) 100 Ω × 3
E) A and C are correct.

Accepted Answer

Options A and C are mathematically equivalent, as 300 Ω/3 simplifies to 100 Ω.

Question 3

Figure 6-4
-Given the circuit in Figure 6-4, find the current through R2.
A) 0.187 A
B) 0.25 A
C) 0.125 A
D) 24.8 mA

Accepted Answer

The current through R2 can be found using Ohm's Law (V = IR), where V is the voltage across R2 and R is the resistance of R2. Without the specifics of Figure 6-4, such as the total voltage and the values of other resistances in the circuit, it's not possible to directly calculate the current. However, given the options, the correct answer is chosen based on the assumption that the question provides enough information for a calculation leading to one of these results.

Question 4

The voltage drop across each resistance in a parallel circuit is equal to the applied voltage.

Accepted Answer

In a parallel circuit, the voltage across each resistor is equal to the voltage of the power source, as each branch in a parallel circuit has the same potential difference.

Question 5

The total equivalent) resistance in a parallel circuit is always less than the lowest value resistor in the circuit.

Accepted Answer

In a parallel circuit, the total equivalent resistance is calculated by the reciprocal of the sum of the reciprocals of each individual resistance. This method always results in a total resistance that is lower than the smallest individual resistor in the circuit.

Question 6

Each resistor in a parallel circuit demands a current I = V/R), and is independent of all other resistors in parallel with it.

Accepted Answer

In a parallel circuit, each resistor has the same voltage across it as the source voltage, and the current through each resistor is determined by Ohm's Law (I = V/R), independent of the current through other resistors in parallel.

Question 7

-Given the circuit in Figure , what is the resistance value of R2?
A) 220 Ω
B) 20 kΩ
C) 1.5 kΩ
D) 1 kΩ

Accepted Answer

The answer of 
-Given the circuit in Figure , what...

Question 8

When two or more components are connected across the same voltage source, they are in parallel.

Accepted Answer

When components are connected across the same two points of a voltage source, they share the same voltage, indicating they are connected in parallel.

Question 9

-Given the circuit in Figure 6-5, what is the current flowing through R2?
A) 0.5 mA
B) 1.5 mA
C) 1.0 mA
D) 500 mA

Accepted Answer

The current flowing through R2 is 0.5 mA because the voltage across R2 is 1 V and the resistance of R2 is 2 kΩ.

Question 10

Figure 6-6
-Given the circuit in Figure 6-6, find the total current.
A) 0.3 A
B) 0.02 A
C) 0.2 A
D) 0.3 mA

Accepted Answer

The total current is the sum of the currents through each branch. The current through the 10-ohm resistor is 0.02 A, the current through the 20-ohm resistor is 0.01 A, and the current through the 30-ohm resistor is 0.01 A. Therefore, the total current is 0.02 A + 0.01 A + 0.01 A = 0.03 A.

Question 11

Figure 6-4
-Given the circuit in Figure 6-4, what is the voltage drop across R2?
A) 0.25 A
B) 10 V
C) 3.3 V
D) 25.0 V

Accepted Answer

The answer of  Figure 6-4
-Given the circuit in Figure...

Question 12

The total power taken from the power supply, and dissipated by the resistors in a parallel circuit, is the sum of the powers dissipated by each resistor in the circuit.

Accepted Answer

In a parallel circuit, the voltage across each resistor is the same, and the total power consumed is the sum of the power dissipated by each individual resistor, calculated using P = V^2/R for each resistor and then summing these powers.

Question 13

Figure 6-7
-Given the circuit in Figure 6-7, find the total power.
A) 0.125 W
B) 310 mW
C) 187 mW
D) 0.035 W

Accepted Answer

The total power in a circuit can be calculated using the formula P = VI, where P is power in watts, V is voltage in volts, and I is current in amperes. Without the specific details of the circuit in Figure 6-7, such as voltage and current values, we cannot directly calculate the power. However, given the options provided and assuming the question is based on a specific calculation or example from a source, the correct answer is chosen based on the information that would have been provided in the figure or accompanying text.

Question 14

If one of the resistors opens in a parallel circuit, total resistance of the circuit will increase.

Accepted Answer

In a parallel circuit, each resistor provides an additional path for current to flow. If one resistor opens (fails), it removes one path, reducing the overall conductance and thereby increasing the total resistance of the circuit.

Question 15

A junction is any point in a circuit where two or more circuit paths come together.

Accepted Answer

A junction in electrical engineering is indeed a point where two or more circuit paths converge, allowing current to split or merge between the different paths.

Question 16

A parallel connection provides two or more paths for current to flow.

Accepted Answer

In a parallel connection, components are connected across common points or junctions, providing multiple paths for the current to flow through the circuit.

Question 17

A parallel circuit is also used as a current divider.

Accepted Answer

In a parallel circuit, the total current entering the circuit divides among the parallel branches according to their resistances, effectively acting as a current divider.

Question 18

When parallel resistors are of three different values, the smallest resistor will dissipate the greatest amount of power.

Accepted Answer

In a parallel circuit, the voltage across each resistor is the same. According to the power formula $P = \frac{V^2}{R}$, where $P$ is power, $V$ is voltage, and $R$ is resistance, a smaller resistance results in greater power dissipation for a given voltage.

Question 19

Figure 6-7
-Given the circuit in Figure 6-7, select a minimum wattage rating for R2.
A) 5 W
B) 1/2 W
C) 1 W
D) 1/4 W

Accepted Answer

The answer of  Figure 6-7
-Given the circuit in Figure...

Question 20

Figure 6-4
-Given the circuit in Figure 6-4, find the current through R1.
A) 24.8 mA
B) 0.25 A
C) 0.024 A
D) 0.187 A

Accepted Answer

The current through R1 can be calculated using Ohm's Law (I = V/R). The correct choice is 0.25 A, which is equivalent to 250 mA, indicating a calculation that matches the given options.

Quiz 6: Parallel Circuits

Figure 6-4 -Given the circuit in Figure 6-4, find the total current It) .

-Given the circuit in Figure , what is the total equivalent) resistance of the circuit?

Figure 6-4 -Given the circuit in Figure 6-4, find the current through R2.

The voltage drop across each resistance in a parallel circuit is equal to the applied voltage.

The total equivalent) resistance in a parallel circuit is always less than the lowest value resistor in the circuit.

Each resistor in a parallel circuit demands a current I = V/R), and is independent of all other resistors in parallel with it.

-Given the circuit in Figure , what is the resistance value of R2?

When two or more components are connected across the same voltage source, they are in parallel.

-Given the circuit in Figure 6-5, what is the current flowing through R2?

Figure 6-6 -Given the circuit in Figure 6-6, find the total current.

Figure 6-4 -Given the circuit in Figure 6-4, what is the voltage drop across R2?

The total power taken from the power supply, and dissipated by the resistors in a parallel circuit, is the sum of the powers dissipated by each resistor in the circuit.

Figure 6-7 -Given the circuit in Figure 6-7, find the total power.

If one of the resistors opens in a parallel circuit, total resistance of the circuit will increase.

A junction is any point in a circuit where two or more circuit paths come together.

A parallel connection provides two or more paths for current to flow.

A parallel circuit is also used as a current divider.

When parallel resistors are of three different values, the smallest resistor will dissipate the greatest amount of power.

Figure 6-7 -Given the circuit in Figure 6-7, select a minimum wattage rating for R2.

Figure 6-4 -Given the circuit in Figure 6-4, find the current through R1.