At equilibrium, for the reaction A + B→C , it is possible to calculate$\triangle$G⁰ as

Name: At equilibrium, for the reaction A + B→C , it is possible to calculate$\triangle$G 0 as
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Question

Quizplus · Accepted Answer

The correct answer is A) -RT ln [C] /[A][B]. This formula is derived from the relationship between the Gibbs free energy change at equilibrium ($\Delta G^0$) and the equilibrium constant (K), where $\Delta G^0 = -RT \ln K$, and K for the reaction A + B → C is given by [C]/[A][B].

At Equilibrium, for the Reaction a + B→C , It △\triangle△

At Equilibrium, for the Reaction a + B→C , It $\triangle$