If the frequencies of two alleles in a population are 0.1 and 0.2, what is the chance that an individual randomly chosen from this population is heterozygous for these two alleles?
A) 0.1 + 0.2 = 30%
B) 0.1 * 0.1 = 1%
C) 0.1 * 0.2 = 2%
D) 2 * 0.1 + 0.2 = 60%
E) 2 * 0.1 * 0.2 = 4%
Correct Answer:
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