Assume that the amount of time that it takes an employee to service a car at an oil change facility follows the uniform probability distribution between 21 and 38 minutes. What is the standard deviation of this distribution?

Question

Quizplus · Accepted Answer

The standard deviation ($\sigma$) of a uniform distribution is calculated using the formula $\sigma = \frac{b-a}{\sqrt{12}}$, where $a$ and $b$ are the minimum and maximum values of the distribution, respectively. Here, $a = 21$ and $b = 38$, so $\sigma = \frac{38-21}{\sqrt{12}} = \frac{17}{\sqrt{12}} \approx 4.91$.

Assume That the Amount of Time That It Takes an Employee