Bob's golf score at his local course follows the normal distribution with a mean of 92.1 and a standard deviation of 3.8. The interval around the mean that contains 68% of Bob's golf scores is -----.

Question

Quizplus · Accepted Answer

The interval that contains 68% of the scores in a normal distribution is defined by one standard deviation above and below the mean. Therefore, we calculate the interval as mean ± standard deviation = 92.1 ± 3.8, which gives us the interval 88.3 to 95.9.

Bob's Golf Score at His Local Course Follows the Normal