The combustion of 0.1240 kg of propane in the presence of excess oxygen produces 0.3110 kg of carbon dioxide. What is the theoretical yield?

Question

Quizplus · Accepted Answer

The balanced equation for the combustion of propane (C3H8) is C3H8 + 5O2 → 3CO2 + 4H2O. The molar mass of propane is 44.1 g/mol, and the molar mass of CO2 is 44.0 g/mol. Theoretical yield of CO2 is calculated based on stoichiometry: (0.1240 kg C3H8) * (1000 g/kg) / (44.1 g/mol) * (3 mol CO2 / 1 mol C3H8) * (44.0 g/mol CO2) = 371.2 g CO2.

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