How many moles of NaOH are needed to neutralize 15.0 mL of 0.235 M HCl solution? Paired item 1)

Question

How many moles of NaOH are needed to neutralize 15.0 mL of 0.235 M HCl solution?  Paired item 1)

Quizplus · Accepted Answer

To neutralize the HCl solution, an equal number of moles of NaOH are needed because the reaction is a 1:1 stoichiometry. The moles of HCl are calculated as $15.0 \, \text{mL} \times 0.235 \, \text{mol/L} = 3.525 \times 10^{-3} \, \text{moles}$. Therefore, $3.53 \times 10^{-3} \, \text{moles}$ of NaOH are needed, matching choice C.

How Many Moles of NaOH Are Needed to Neutralize 15