The weights (in kilograms) of a group of crates being shipped to Panama are 95, 103, 110, 104, 105, 112 and 92. What is the mean deviation?
A) 5.43 kg
B) 6.25 kg
C) 0.53 kg
D) 52.50 kg
E) None of the choices are correct.

Question

Quizplus · Accepted Answer

To find the mean deviation, first calculate the mean of the weights: (95 + 103 + 110 + 104 + 105 + 112 + 92) / 7 = 103 kg. Then, find the absolute deviations from the mean: |95-103|, |103-103|, |110-103|, |104-103|, |105-103|, |112-103|, |92-103|, which are 8, 0, 7, 1, 2, 9, and 11 respectively. The mean deviation is the average of these absolute deviations: (8 + 0 + 7 + 1 + 2 + 9 + 11) / 7 = 5.43 kg.

The Weights (In Kilograms) of a Group of Crates Being