Solve the equation using the quadratic formula.
-$$8 x ^ { 2 } + 1 = 3 x$$
A) $\left\{ \frac { 3 \pm i \sqrt { 23 } } { 16 } \right\}$
B) $\left\{ \frac { - 3 \pm i \sqrt { 23 } } { 16 } \right\}$
C) $\left\{ \frac { 3 \pm \sqrt { 23 } } { 16 } \right\}$
D) $\left\{ \frac { - 3 \pm \sqrt { 23 } } { 16 } \right\}$

Question

Quizplus · Accepted Answer

The quadratic equation is $8x^2 - 3x + 1 = 0$. Using the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 8$, $b = -3$, and $c = 1$, the discriminant $b^2 - 4ac = 9 - 32 = -23$, which is negative, leading to complex roots: $\frac{3 \pm i\sqrt{23}}{16}$.

Solve the Equation Using the Quadratic Formula 8x2+1=3x8 x ^ { 2 } + 1 = 3 x8x2+1=3x

Solve the Equation Using the Quadratic Formula $8 x ^ { 2 } + 1 = 3 x$