Solve the equation by the method of your choice.
-$$4 x ^ { 2 } - 19 x - 5 = 0$$
A) $\{ - 4,5 \}$
B) $\left\{ - \frac { 1 } { 4 } , \frac { 1 } { 19 } \right\}$
C) $\left\{ - \frac { 1 } { 4 } , 5 \right\}$
D) $\left\{ - \frac { 1 } { 4 } , 4 \right\}$

Question

Quizplus · Accepted Answer

To solve the quadratic equation $4x^2 - 19x - 5 = 0$, we can use the quadratic formula $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$, where $a = 4$, $b = -19$, and $c = -5$. Plugging these values into the formula gives two solutions: $x = -\frac{1}{4}$ and $x = 5$, which matches option C.

Solve the Equation by the Method of Your Choice 4x2−19x−5=04 x ^ { 2 } - 19 x - 5 = 04x2−19x−5=0

Solve the Equation by the Method of Your Choice $4 x ^ { 2 } - 19 x - 5 = 0$