Write a quadratic equation having the given solutions.
-$$\frac { 1 } { 3 } , \frac { 1 } { 6 }$$
A) $x ^ { 2 } - \frac { 1 } { 18 } x + \frac { 1 } { 2 } = 0$
B) $x ^ { 2 } + \frac { 1 } { 2 } x + \frac { 1 } { 18 } = 0$
C) $x ^ { 2 } - \frac { 1 } { 2 } x + \frac { 1 } { 18 } = 0$
D) $x ^ { 2 } + \frac { 1 } { 18 } x + \frac { 1 } { 2 } = 0$

Question

Quizplus · Accepted Answer

Given the solutions $\frac{1}{3}$ and $\frac{1}{6}$, the quadratic equation can be formed by the product $(x - \frac{1}{3})(x - \frac{1}{6}) = 0$. Expanding this gives $x^2 - \frac{1}{2}x + \frac{1}{18} = 0$, which matches option C.

Write a Quadratic Equation Having the Given Solutions 13,16\frac { 1 } { 3 } , \frac { 1 } { 6 }31​,61​

Write a Quadratic Equation Having the Given Solutions $\frac { 1 } { 3 } , \frac { 1 } { 6 }$