Make an appropriate substitution in order to obtain a quadratic equation. Find all complex values for x.
-$x-10 x^{1 / 2}+24=0$
A) $x = \pm \sqrt { 6 } , \pm 2$
B) $x = 6,4$
C) $x = 36,16$
D) $x = \pm 6 , \pm 4$

Question

Quizplus · Accepted Answer

Let $y = x^{1/2}$, then the equation becomes $y^2 - 10y + 24 = 0$. Solving this quadratic equation gives $y = 6$ or $y = 4$. Since $y = x^{1/2}$, we have $x = y^2$, which gives $x = 36$ or $x = 16$.

Make an Appropriate Substitution in Order to Obtain a Quadratic x−10x1/2+24=0x-10 x^{1 / 2}+24=0x−10x1/2+24=0

Make an Appropriate Substitution in Order to Obtain a Quadratic $x-10 x^{1 / 2}+24=0$