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Question 107
Solve.- 1x2−11x+18=2xx−9−xx−2\frac { 1 } { x ^ { 2 } - 11 x + 18 } = \frac { 2 x } { x - 9 } - \frac { x } { x - 2 }x2−11x+181=x−92x−x−2x
A) {5−212,5+212}\left\{ \frac { 5 - \sqrt { 21 } } { 2 } , \frac { 5 + \sqrt { 21 } } { 2 } \right\}{25−21,25+21} B) {−5−292,−5+292}\left\{ \frac { - 5 - \sqrt { 29 } } { 2 } , \frac { - 5 + \sqrt { 29 } } { 2 } \right\}{2−5−29,2−5+29} C) {−5−212,−5+212}\left\{ \frac { - 5 - \sqrt { 21 } } { 2 } , \frac { - 5 + \sqrt { 21 } } { 2 } \right\}{2−5−21,2−5+21} D) {5−292,5+292}\left\{ \frac { 5 - \sqrt { 29 } } { 2 } , \frac { 5 + \sqrt { 29 } } { 2 } \right\}{25−29,25+29}
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