Solve.
-$$x ^ { 3 } + x + 2 x ^ { 2 } + 2 = 0$$
A) $\{ 2 , - i , i \}$
B) $\{ - 1,1,2 i , - 2 i \}$
C) $\{ - 2 , - i , i \}$
D) $\{ - 1,1,2 , - 2 \}$

Name: Solve. -\[x ^ { 3 } + x + 2 x ^ { 2 } + 2 = 0\] A) $\{ 2 , - i , i \}$ B) $\{ - 1,1,2 i , - 2 i \}$ C) $\{ - 2 , - i , i \}$ D) $\{ - 1,1,2 , - 2 \}$
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Question

Quizplus · Accepted Answer

The polynomial can be factored as $(x + 2)(x^2 + 1) = 0$, giving roots $x = -2$ and $x^2 + 1 = 0$ which gives $x = \pm i$.

Solve - x3+x+2x2+2=0x ^ { 3 } + x + 2 x ^ { 2 } + 2 = 0x3+x+2x2+2=0

Solve
- $x ^ { 3 } + x + 2 x ^ { 2 } + 2 = 0$