Question 1

Solve the problem.
-The maximum distance $\mathrm { d }$ in kilometers that you can see from a height $h$ in meters is given by the formula $d = 3.5 \sqrt { h }$. How high above the ground must you be to see 40 kilometers? Round to the nearest tenth of a meter.
A) $457.1 \mathrm {~m}$
B) $130.6 \mathrm {~m}$
C) $11.4 \mathrm {~m}$
D) $22.1 \mathrm {~m}$

Accepted Answer

The answer of Solve the problem.
-The maximum distance \(\mathrm {...

Question 2

Solve the problem.
-Police use the formula s $= \sqrt { 30 f d }$ to estimate the speed s of a car in miles per hour, where $d$ is the distance in feet that the car skidded and $\mathrm { f }$ is the coefficient of friction. If the coefficient of friction on a certain dry road is $0.84$ and a car was traveling on it at a rate of $40 \mathrm { mph }$, how far will the car skid? Round to the nearest foot.
A) $32 \mathrm { ft }$
B) $53 \mathrm { ft }$
C) $403 \mathrm { ft }$
D) $63 \mathrm { ft }$

Accepted Answer

The answer of Solve the problem.
-Police use the formula s...

Quiz 7: Rational Exponents, Radicals, and Complex Numbers

Solve the problem. -The maximum distance $\mathrm { d }$ in kilometers that you can see from a height $h$ in meters is given by the formula $d = 3.5 \sqrt { h }$ . How high above the ground must you be to see 40 kilometers? Round to the nearest tenth of a meter.

Quiz 7: Rational Exponents, Radicals, and Complex Numbers

Solve the problem. -The maximum distance d\mathrm { d }d in kilometers that you can see from a height hhh in meters is given by the formula d=3.5hd = 3.5 \sqrt { h }d=3.5h​ . How high above the ground must you be to see 40 kilometers? Round to the nearest tenth of a meter.

Solve the problem. -The maximum distance $\mathrm { d }$ in kilometers that you can see from a height $h$ in meters is given by the formula $d = 3.5 \sqrt { h }$ . How high above the ground must you be to see 40 kilometers? Round to the nearest tenth of a meter.