The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
-$x^{2}+2 x+y^{2}-4 y-19=0$

A) center $( 1,2 ) ;$ radius $= 2 \sqrt { 6 }$
B) center $( 1 , - 2 )$; radius $= 2 \sqrt { 6 }$
C) center $( - 1,2 )$; radius $= 2 \sqrt { 6 }$
D) center $( - 1,2 )$; radius $= 24$

Question

The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
-$x^{2}+2 x+y^{2}-4 y-19=0$
 
A) center $( 1,2 ) ;$ radius $= 2 \sqrt { 6 }$ 
B) center $( 1 , - 2 )$; radius $= 2 \sqrt { 6 }$ 
C) center $( - 1,2 )$; radius $= 2 \sqrt { 6 }$ 
D) center $( - 1,2 )$; radius $= 24$

Quizplus · Accepted Answer

The Answer of The graph of the equation is a circle. Find the center and the radius, and then graph the circle.
-$x^{2}+2 x+y^{2}-4 y-19=0$
 
A) center $( 1,2 ) ;$ radius $= 2 \sqrt { 6 }$ 
B) center $( 1 , - 2 )$; radius $= 2 \sqrt { 6 }$ 
C) center $( - 1,2 )$; radius $= 2 \sqrt { 6 }$ 
D) center $( - 1,2 )$; radius $= 24$

The Graph of the Equation Is a Circle x2+2x+y2−4y−19=0x^{2}+2 x+y^{2}-4 y-19=0x2+2x+y2−4y−19=0

The Graph of the Equation Is a Circle $x^{2}+2 x+y^{2}-4 y-19=0$