Find the center and the radius of the circle.
-$$x ^ { 2 } + y ^ { 2 } + 12 x - 2 y + 33 = 0$$
A) center $( 6 , - 1 )$, radius $= 4$
B) center $( - 6,1 )$, radius $= 4$
C) center $( - 6,1 )$, radius $= 2$
D) center $( 6 , - 1 )$, radius $= 2$

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The Answer of Find the center and the radius of the circle.
-$$x ^ { 2 } + y ^ { 2 } + 12 x - 2 y + 33 = 0$$
A) center $( 6 , - 1 )$, radius $= 4$
B) center $( - 6,1 )$, radius $= 4$
C) center $( - 6,1 )$, radius $= 2$
D) center $( 6 , - 1 )$, radius $= 2$

Find the Center and the Radius of the Circle x2+y2+12x−2y+33=0x ^ { 2 } + y ^ { 2 } + 12 x - 2 y + 33 = 0x2+y2+12x−2y+33=0

Find the Center and the Radius of the Circle $x ^ { 2 } + y ^ { 2 } + 12 x - 2 y + 33 = 0$