Find the center and the radius of the circle.
-$$( x + 8 ) ^ { 2 } + y ^ { 2 } = 36$$
A) center $( 0 , - 8 )$; radius $= 6$
B) center $( - 8,0 )$; radius $= 6$
C) center $( 8,0 )$; radius $= 6$
D) center $( - 8,0 )$; radius $= 36$

Question

Quizplus · Accepted Answer

The equation of a circle in the form $(x - h)^2 + (y - k)^2 = r^2$ has a center at $(h, k)$ and a radius of $r$. In the given equation, $x + 8$ suggests the center's x-coordinate is $-8$ and there's no shift in the y-coordinate, so $k = 0$. The radius is the square root of $36$, which is $6$.

Find the Center and the Radius of the Circle (x+8)2+y2=36( x + 8 ) ^ { 2 } + y ^ { 2 } = 36(x+8)2+y2=36

Find the Center and the Radius of the Circle $( x + 8 ) ^ { 2 } + y ^ { 2 } = 36$