Find the center and the radius of the circle.
-$$x ^ { 2 } + y ^ { 2 } - 18 x + 6 y + 54 = 0$$
A) center $( - 9,3 )$, radius $= 36$
B) center $( 9 , - 3 )$, radius $= 6$
C) center $( - 3,9 )$, radius $= 6$
D) center $( 3 , - 9 )$, radius $= 36$

Question

Quizplus · Accepted Answer

The equation can be rewritten in the standard form of a circle by completing the square: $(x - 9)^2 + (y + 3)^2 = 36$. Thus, the center is $(9, -3)$ and the radius is $6$.

Find the Center and the Radius of the Circle x2+y2−18x+6y+54=0x ^ { 2 } + y ^ { 2 } - 18 x + 6 y + 54 = 0x2+y2−18x+6y+54=0

Find the Center and the Radius of the Circle $x ^ { 2 } + y ^ { 2 } - 18 x + 6 y + 54 = 0$