Solve the problem.
-A contractor builds a swimming pool with cross section in the shape of a trapezoid. The deep end is 9 ft deep and the shallow end is 3 ft deep. The length of the pool is 60 ft and the width is 25 ft. AsThe pool is being filled, find the volume of water when the depth is 4 ft.
A) $4,500 \mathrm { ft } ^ { 3 }$
B) $4,000 \mathrm { ft } ^ { 3 }$
C) $1,620 \mathrm { ft } ^ { 3 }$
D) $2,000 \mathrm { ft } ^ { 3 }$

Question

Solve the problem.
-A contractor builds a swimming pool with cross section in the shape of a trapezoid. The deep end is 9 ft deep and the shallow end is 3 ft deep. The length of the pool is 60 ft and the width is 25 ft. AsThe pool is being filled, find the volume of water when the depth is 4 ft. 
A) $4,500 \mathrm { ft } ^ { 3 }$
B) $4,000 \mathrm { ft } ^ { 3 }$
C) $1,620 \mathrm { ft } ^ { 3 }$
D) $2,000 \mathrm { ft } ^ { 3 }$

Quizplus · Accepted Answer

The volume of water when the depth is 4 ft can be calculated using the formula for the volume of a trapezoidal prism: $ V = \frac{1}{2} \times (b_1 + b_2) \times h \times l $, where $ b_1 $ and $ b_2 $ are the depths at the shallow and deep ends, $ h $ is the width, and $ l $ is the length. Here, $ b_1 = 3 $ ft, $ b_2 = 4 $ ft, $ h = 25 $ ft, and $ l = 60 $ ft. So, $ V = \frac{1}{2} \times (3 + 4) \times 25 \times 60 = 2,000 \mathrm { ft } ^ { 3 } $.

Solve the Problem 4,500ft34,500 \mathrm { ft } ^ { 3 }4,500ft3

Solve the Problem $4,500 \mathrm { ft } ^ { 3 }$