Factor by grouping.
-$8 x ^ { 2 } + 10 x + 12 x + 15$
A) $( 2 x - 3 ) ( 4 x - 5 )$
B) $( 2 x + 3 ) ( 4 x + 5 )$
C) $( 8 x + 3 ) ( x + 5 )$
D) $( 8 x - 3 ) ( x - 5 )$

Question

Quizplus · Accepted Answer

First, group the terms: $8x^2 + 10x$ and $12x + 15$. Factoring out the greatest common factor from each group gives $2x(4x + 5) + 3(4x + 5)$. Then, factor out the common factor $(4x + 5)$, resulting in $(2x + 3)(4x + 5)$.

Factor by Grouping 8x2+10x+12x+158 x ^ { 2 } + 10 x + 12 x + 158x2+10x+12x+15

Factor by Grouping $8 x ^ { 2 } + 10 x + 12 x + 15$