Factor by grouping.
-$10 x ^ { 6 } - 25 x ^ { 3 } + 8 x ^ { 3 } - 20$
A) $\left( 5 x ^ { 6 } + 4 \right) ( 2 x - 5 )$
B) $\left( 10 x ^ { 3 } - 4 \right) \left( x ^ { 3 } + 5 \right)$
C) $\left( 5 x ^ { 3 } + 4 \right) \left( 2 x ^ { 3 } - 5 \right)$
D) $\left( 5 x ^ { 3 } - 4 \right) \left( 2 x ^ { 3 } + 5 \right)$

Question

Quizplus · Accepted Answer

First, combine like terms: $10x^6 - 25x^3 + 8x^3 - 20 = 10x^6 - 17x^3 - 20$. Factoring by grouping, we can factor out a $5x^3$ from the first two terms and a 4 from the last two terms, giving us $5x^3(2x^3 - 5) + 4(2x^3 - 5)$, which simplifies to $(5x^3 + 4)(2x^3 - 5)$.

Factor by Grouping 10x6−25x3+8x3−2010 x ^ { 6 } - 25 x ^ { 3 } + 8 x ^ { 3 } - 2010x6−25x3+8x3−20

Factor by Grouping $10 x ^ { 6 } - 25 x ^ { 3 } + 8 x ^ { 3 } - 20$