Write the function without radicals by using fractional exponents.
-$$y = \sqrt [ 3 ] { x ^ { 2 } + 6 }$$
A) $y = \left( x ^ { 2 } + 6 \right) ^ { 3 }$
B) $y = x ^ { 2 / 3 } + 6$
C) $y = \log \left( x ^ { 2 } + 6 \right)$
D) $y = \left( x ^ { 2 } + 6 \right) ^ { 1 / 3 }$

Question

Quizplus · Accepted Answer

The cube root of a number can be expressed as that number raised to the power of $1/3$, so $\sqrt[3]{x^2 + 6}$ is equivalent to $(x^2 + 6)^{1/3}$.

Write the Function Without Radicals by Using Fractional Exponents y=x2+63y = \sqrt [ 3 ] { x ^ { 2 } + 6 }y=3x2+6​

Write the Function Without Radicals by Using Fractional Exponents $y = \sqrt [ 3 ] { x ^ { 2 } + 6 }$