Rewrite the expression as a sum, difference, or multiple of logarithms.
-Find where $f ^ { \prime } ( x ) = 0$ if $f ^ { \prime } ( x ) = 3 x ^ { 3 } + 17 x ^ { 2 } - 6 x$.
A) $x = 0 , x = - \frac { 1 } { 3 } , x = - 6$
B) $x = 0 , x = - \frac { 1 } { 3 } , x = 6$
C) $x = 0 , x = \frac { 1 } { 6 } , x = 6$
D) $x = 0 , x = \frac { 1 } { 3 } , x = - 6$

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The Answer of Rewrite the expression as a sum, difference, or multiple of logarithms.
-Find where $f ^ { \prime } ( x ) = 0$ if $f ^ { \prime } ( x ) = 3 x ^ { 3 } + 17 x ^ { 2 } - 6 x$.
A) $x = 0 , x = - \frac { 1 } { 3 } , x = - 6$
B) $x = 0 , x = - \frac { 1 } { 3 } , x = 6$
C) $x = 0 , x = \frac { 1 } { 6 } , x = 6$
D) $x = 0 , x = \frac { 1 } { 3 } , x = - 6$

Rewrite the Expression as a Sum, Difference, or Multiple of Logarithms