Find the exact value of the real number y.
-$$y = \arccos \left( - \frac { \sqrt { 2 } } { 2 } \right)$$

Name: Find the exact value of the real number y. -\[y = \arccos \left( - \frac { \sqrt { 2 } } { 2 } \right)\]
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Quizplus · Accepted Answer

The value of $\arccos \left( - \frac { \sqrt { 2 } } { 2 } \right)$ corresponds to the angle in the unit circle whose cosine value is $-\frac{\sqrt{2}}{2}$. This value is found in the second quadrant where the angle from the positive x-axis is $\frac{3\pi}{4}$.

Find the Exact Value of the Real Number Y y=arccos⁡(−22)y = \arccos \left( - \frac { \sqrt { 2 } } { 2 } \right)y=arccos(−22​​)

Find the Exact Value of the Real Number Y $y = \arccos \left( - \frac { \sqrt { 2 } } { 2 } \right)$