Give the degree measure of $$\theta$$
-$$\theta = \sec ^ { - 1 } ( - \sqrt { 2 } )$$

Name: Give the degree measure of \[\theta\] -\[\theta = \sec ^ { - 1 } ( - \sqrt { 2 } )\]
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Question

Quizplus · Accepted Answer

The secant function, $\sec(\theta)$, is the reciprocal of the cosine function. Therefore, $\sec^{-1}(-\sqrt{2})$ implies $\cos(\theta) = -\frac{1}{\sqrt{2}}$. The angle $\theta$ that satisfies this condition in the range $[0^\circ, 180^\circ]$ is $135^\circ$, where the cosine value is negative and equals $-\frac{1}{\sqrt{2}}$.

Give the Degree Measure Of θ\thetaθ - θ=sec⁡−1(−2)\theta = \sec ^ { - 1 } ( - \sqrt { 2 } )θ=sec−1(−2​)

Give the Degree Measure Of $\theta$ - $\theta = \sec ^ { - 1 } ( - \sqrt { 2 } )$