A fast-food restaurant chain with 700 outlets in the United States has recorded the geographic location of its restaurants in the accompanying table of percentages. One restaurant is to be chosen at random from the 700 to test market a new chicken sandwich. $$\begin{array}{r} \text { Region }\ \begin{array} { r r c c c c } \hline & & \text { NE } & \text { SE } & \text { SW } & \text { NW } \ \hline & 100,000 & 20 \% & 4 \% & 9 \% & 11 \% \ \hline \end{array} \end{array}$$ What is the probability that the restaurant is located in the northern portion of the United States? A) 0.56 B) 0.40 C) 0.16 D) 0.44

Question

A fast-food restaurant chain with 700 outlets in the United States has recorded the geographic location of its restaurants in the accompanying table of percentages. One restaurant is to be chosen at random from the 700 to test market a new chicken sandwich. $$\begin{array}{r}
\text { Region }\
\begin{array} { r r c c c c } 
\hline & & \text { NE } & \text { SE } & \text { SW } & \text { NW } \
\hline & < 10,000 & 5 \% & 6 \% & 3 \% & 0 \% \
\text { Population of City } & 10,000 - 100,000 & 15 \% & 10 \% & 12 \% & 5 \% \
& > 100,000 & 20 \% & 4 \% & 9 \% & 11 \% \
\hline
\end{array}
\end{array}$$ What is the probability that the restaurant is located in the northern portion of the United States?
A) 0.56
B) 0.40
C) 0.16
D) 0.44

Quizplus · Accepted Answer

The northern portion of the United States includes the NE and NW regions. The probability of selecting a restaurant in the NE region is 5% + 15% + 20% = 40%. The probability of selecting a restaurant in the NW region is 0% + 5% + 11% = 16%. Therefore, the probability of selecting a restaurant in the northern portion of the United States is 40% + 16% = 56%.

A Fast-Food Restaurant Chain with 700 Outlets in the United