The table displays the probabilities for each of the six outcomes when rolling a particular unfair die. Suppose that the die is rolled once. Let A be the event that the number rolled is less than 4, and let B be the event that the number rolled is odd. Find P(A ? B). $$\begin{array} { | l | l | l | l | l | l | l | }
\hline \text { Outcome } & 1 & 2 & 3 & 4 & 5 & 6 \
\hline \text { Probability } & .1 & .1 & .1 & .2 & .2 & .3 \
\hline
\end{array}$$
A) .5
B) .2
C) .3
D) .7

Question

The table displays the probabilities for each of the six outcomes when rolling a particular unfair die. Suppose that the die is rolled once. Let A be the event that the number rolled is less than 4, and let B be the event that the number rolled is odd. Find P(A ? B). $$\begin{array} { | l | l | l | l | l | l | l | } 
\hline \text { Outcome } & 1 & 2 & 3 & 4 & 5 & 6 \
\hline \text { Probability } & .1 & .1 & .1 & .2 & .2 & .3 \
\hline
\end{array}$$
A) .5
B) .2
C) .3
D) .7

Quizplus · Accepted Answer

P(A) = P(1) + P(2) + P(3) = 0.1 + 0.1 + 0.1 = 0.3P(B) = P(1) + P(3) + P(5) = 0.1 + 0.1 + 0.2 = 0.4P(A ? B) = P(A) + P(B) - P(A ? B) = 0.3 + 0.4 - 0.1 = 0.6

The Table Displays the Probabilities for Each of the Six