Solve the problem.
-A projectile is fired with an initial velocity of 450 feet per second at an angle of $$70 ^ { \circ }$$ with the horizontal. To the nearest 10 feet, find the horizontal distance covered by the projectile.
A) 4310 ft
B) 3930 ft
C) 4070 ft
D) 4180 ft

Question

Quizplus · Accepted Answer

The horizontal distance can be found using the formula: $$ R = \frac{v^2 \sin(2\theta)}{g} $$, where $ v = 450 $ ft/s, $ \theta = 70^\circ $, and $ g = 32.2 $ ft/s². Calculating gives approximately 4070 ft.

Solve the Problem 70∘70 ^ { \circ }70∘ With the Horizontal

Solve the Problem $70 ^ { \circ }$ With the Horizontal